| Statistical Indices of Data Variability
Measures of Central Tendency, Mode, Median and Mean,
and their Corresponding Measures of Spread
Mode:
The most frequently occurring score. For example, the May QPE scores for Internal
Medicine indicated that the score 26.2 was obtained by eight students in the Year 2 class.
Range
The spread of scores is indicated by an expression of the difference between the
lowest and highest scores. For example, the Internal Medicine scores ranged from 15
percent correct to 43.9 percent correct; therefore, the range was (43.9-15)=28.9 for this
data.
Median:
The midpoint of a distribution, above which half of the scores occurred and below
which half of the scores occurred.
Interquartile Range:
The difference between the score representing the 75th percentile and the score
representing the 25th percentile. For example, the 75th percentile of the Internal
Medicine data was 32.6 percent correct and the 25th percentile was 24.2 percent correct;
therefore, the interquartile range was (32.6-24.2)=8.4 for this data. Thus, 50% of the
Year 2 Internal Medicine scores fell within an 8.4 point range.
Mean:
More accurately called the arithmetic mean, it is defined as the sum of scores
divided by the number of scores. Or, put in other terms, the mean is the sum of measures
observed divided by the number of observations.
Standard Deviation:
The standard deviation is the square root of the average squared deviation from the
mean. The standard deviation of the Year 2 Internal Medicine scores was 6.9; therefore, we
can conclude that 68% of the class fell within plus or minus 6.9 points of the mean.
Understanding and Calculating the Standard Deviation
Computers are used extensively for calculating the standard deviation and other
statistics.
Two methods of calculating the standard deviation are described
in order to elucidate the mathematics involved.
The deviation method is considered first, since it closely
parallels the concept of standard deviation. The raw score method
is presented as a convenient computation alternative.
Deviation method for calculating
standard deviation
Consider the observations 8,25,7,5,8,3,10,12,9.
- First, calculate the mean and determine N.
- Remember, the mean is the sum of scores divided by N where N
is the number of scores.
- Therefore, the mean = (8+25+7+5+8+3+10+12+9) / 9 or 9.67
- Then, calculate the standard deviation as illustrated below.
| Score |
Mean |
Deviation* |
Squared Deviation |
| 8 |
9.67 |
-1.67 |
2.79 |
| 25 |
9.67 |
+15.33 |
235.01 |
| 7 |
9.67 |
-2.67 |
7.13 |
| 5 |
9.67 |
-4.67 |
21.81 |
| 8 |
9.67 |
-1.67 |
2.79 |
| 3 |
9.67 |
-6.67 |
44.49 |
| 10 |
9.67 |
+.33 |
.11 |
| 12 |
9.67 |
+2.33 |
5.43 |
| 9 |
9.67 |
-.67 |
.45 |
| Sum of squared dev = 320.01 |
| *Deviation = Score - Mean |
Standard Deviation = Square root(sum of squared deviations / (N-1)
| |
= Square root(320.01/(9-1)) |
| |
= Square root(40) |
| |
= 6.32 |
Raw score method for calculating
standard deviation
Again, consider the observations 8,25,7,5,8,3,10,12,9.
- First, square each of the scores.
- Determine N, which is the number of scores.
- Compute the sum of X and the sum of X-squared.
- Then, calculate the standard deviation as illustrated below.
| Score |
X2 |
|
| 8 |
64 |
|
| 25 |
625 |
|
| 7 |
49 |
N=9 |
| 5 |
25 |
|
| 8 |
64 |
Sum of X=87 |
| 3 |
9 |
|
| 10 |
100 |
Sum of X2=1161 |
| 12 |
144 |
|
| 9 |
81 |
|
| --- |
--- |
|
| 87 |
1161 |
|
Standard Deviation = square root[(sum of X2)-((sum of X)*(sum of X)/N)/(N-1)]
| |
= square root[(1161)-(87*87)/9)/(9-1)] |
| |
= square root[(1161-(7569/9)/8)] |
| |
= square root[(1161-841)/8] |
| |
= square root[320/8] |
| |
= square root[40] |
| |
= 6.32 |
Even simple statistics, such as the standard
deviation, are tedious to calculate "by hand".
Copyright © 1997 T. Lee Willoughby
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